The reaction of trans-[RuLCl2]+(L = 1,5,9,13-tetramethyl-1,5,9,13-tetraazacyclohexadecane) with NO2-in water at 60 °C leads to the formation of trans-[RuL(O)Cl]+and trans-[RuL(OH)(NO)]2+. The formation of the products can be rationalized by the disproportionation of trans-[RuL(Cl)(NO2)]+. The structures of the products have been determined by X-ray crystallography: trans-[RuL(O)Cl]ClO4, space group Pna21(no. 33), a = 12.616(1), b = 15.421(3), c = 11.292(3) Å; Ru=O and Ru-Cl 1.75(1) and 2.435(6) Å; trans-[RuL(OH)(NO)][ClO4]2, space group Pbca (no. 61), a = 20.459(3), b = 29.16(1), c = 25.13(1) Å; average Ru-OH and Ru-NO 1.906(9) and 1.74(1) Å.
|Number of pages||5|
|Journal||Journal of the Chemical Society, Dalton Transactions|
|Publication status||Published - 1 Dec 1992|
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